Consider a square of side c and draw a four right angle triangle on each side in such a way that side of square is hypotenuse of a triangle as shown in fig,
Now outer square is of length a+b so its area is . Here area of inner square of side c is and as we know area of trigle is 1/2*height*base. In this case the area of triangle becomes . so area of such four triangle is .
Now area of outer square = the sum of areas of inner sqaure and four triangles.
It gives,
Hence proved.
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